35*(x+2)^(3)+(x-2)^(3)

x+8=12, (ii) 15-x=3 and verify: 19x- "13=11x+35, (ii) 2(x-2)-3(x-3)=5(x-5)

If alpha,beta are the roots of the equation 2x^(2)-35x+2=0, the find the value of (2 alpha-35)^(3)(2 beta-35)^(3)

Evaluate the following integrals: (1-35)int_(-2)^(2)(3x^(3)+2|x|+1)/(x^(2)+|x|+1)dx

alpha and beta are roots of the equation 2x ^(2)-35x+2=0. Find the value of sqrt((2alpha -35 )^(3) (2beta-35)^(2))

Show that int_(2)^(2sqrt(3)) x^(3)(x^(2)-3)^(3//2)dx = (16012)/(35)

5x-(13)/(2)x^(2)+(35)/(3)x^(3)-(97)/(4)x^(4)+....=

Factorize: (3)/(2)x^(2)-8x-(35)/(2) .

Solve by factorization: (x-2)/(x-3)+(x-4)/(x-5)=(10)/(3);quad x!=3,5