((cos theta-cos3 theta)/(sin5 theta-sin theta))*((sin8 theta+sin2 theta)/(cos4 theta-cos6 theta))=1

Show that :((cos theta-cos3 theta)(sin8 theta+sin2 theta))/((sin5 theta-sin theta)(cos4 theta-cos6 theta))=1

Prove that ((cos theta-cos 3 theta)(sin 8 theta +sin 2 theta))/((sin 5 theta-sin theta)(cos 4 theta-cos 6 theta))=1

(cos6 theta-cos4 theta)/(sin6 theta+sin4 theta)=-tan theta

Show that ((cos theta - cos 3theta)(sin 8theta + sin 2 theta))/((sin 5 theta - sin theta)(cos 4 theta - cos 6 theta)) = 1

Show that ((cos theta - cos 3 theta) (sin 8 theta + sin 2 theta))/((sin 5 theta - sin theta) (cos 4 theta- cos 6 theta))=1

(sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta)= ________

(cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)

(sin theta-cos theta)/(sin theta+cos theta)+(sin theta+cos theta)/(sin theta-cos theta)=(2)/((2sin^(2)theta-1))

((cos theta - cos 3 theta ) ( sin 8 theta + sin 2 theta ))/(( sin 5 theta - sin theta )( cos 4 theta - cos 6 theta ))=

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta