In a `DeltaABC` if `Delta<=1/4sqrt(abc(a+b+c))` then the triangle is

In a DeltaABC , 2 Delta (cot B + cot C)=

In DeltaABC , 4Delta (cot A+ cot B + cot C) =

In DeltaABC ~ Delta DEF and ar (DeltaABC) = 100 cm^(2), ar (Delta DEF) = 196 cm^(2) and DE = 7 cm , then find AB.

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

If in a DeltaABC,Delta = ( c + a - b) (a + b - c), then tan A is equal to

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

If in a DeltaABC,Delta = ( c + a - b) (a + b - c), then tan A is equal to

Given two triangles ABC and DEF such that DeltaABC ~ Delta DEF . Also, ar(DeltaABC)= 25cm^(2), ar (Delta DEF)= 64cm^(2) and AB=5cm . Then length of side DE is