" (iv) "(1)/(2x)+(1)/(3y)=2quad " And "(1)/(3x)+(1)/(2y)=2(1)/(6)

Solve the following system of equations: (1)/(2x)+(1)/(3y)=2,quad (1)/(3x)+(1)/(2y)=(13)/(6)

Find the value of x and y (1)/(2x)+(1)/(3y)=2 (1)/(3x)+(1)/(2y)=(13)/(6)

Solve the following system of equations: 1/(2x)+1/(3y)=2,\ \ \ 1/(3x)+1/(2y)=(13)/6

( 1 ) /( 2x ) + (1 ) /( 3y ) = 2, (1) /( 3x ) + (1) /( 2y ) = ( 13) /( 6) ( x ne 0 , y ne 0 )

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

Solve for x and y(3)/(x)+(2)/(y)=6 and (1)/(y)-(1)/(2x)=2

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

The lines (x)/(1)=(y)/(2)=(z)/(3) and (x-1)/(-2)=(y-2)/(-4)=(3-z)/(6) are

solve for x and y . (5)/(x-1)+(1)/(y-2) =2 and ( 6) / ( x-1) -(3)/ (y-2) =1