`16 x^2=8x-1`

The area of a square park is 16x^2+8x+1 . What is the length of the park? एक वर्ग पार्क का क्षेत्रफल 16x^2+8x+1 .पार्क की लंबाई कितनी है?

[16x^(2)-8x+1=0,100y^(2)-20y+1=0

Let f: defined from (1//4,oo) to R^(+) as, f(x)=log_(1//4)(x-(1)/(4))+(1)/(2)log_(4)(16x^(2)-8x+1) Statement-1: f(x) is neither injective nor surjective . Statement-1: f(x) is a constant function.

Factorise : 16 x^(2) - 8x - 3

The roots of the roots of the equation x^(2)-8x-16=0

Evaluate int (dx)/sqrt((16+x^2-8x))

lim_(x to 1//2) (8x^(3) - 1)/(16 x^(4) - 1) is equal to

lim_(x to 1//2) (8x^(3) - 1)/(16 x^(4) - 1) is equal to