If `log_2 x+log_4 y+log_4 z=2` then `x^2yz=`

Solve for x, y , z . log_2 x + log_4 y + log_4 z =2 log_3 y + log_9 z + log_9 x =2 log_4 z + log_16 x + log_16 y =2

If log_2 log_3 log_4 (x+1) =0, then x is :-

If log_(4)(log_(2)x) + log_(2) (log_(4) x) = 2 , then find log_(x)4 .

If log_2 (log_3 (log_4 x))= 0, log_4 (log_3 (log_2 y))= 0 and log_3(log_4 (log_2z ))= 0, then the correct option is

Solve : log_2 x + log_4 (x+2) = 2

Calculate : log_(x^2)x xx log_(y^2)y xx log_(z^2)z