[2xx-y+3z=9],[x+y+z=6],[x-y+z=2]

Solve the following equations using Cramer's Rule: 2x-y+3z=9,x+y+z=6,x-y+z=2

Find the value of x,y,z using Cramer's Rule 2x-y+3z=9,x+y+z=6,x-y+z=2

By using Cramer's rule solve 2x-y+3z=9,x+y+z=6,x+y+z=2 .

Statement - I The soluton of the system of equations 2x-y+3z=9,x+y+z=6,x-y+z=2 is x=1,y=2,z=3 Statement - II : The solution of the system of equations x+2y-z=3,3x=y+2z=1 , 2x-2y+3z=2 is x=-1,y=4,z=4 Which of the above Statement(s) is true ?

Solve 2x-y+3z=9,x+y+z=6 and x-y+z=2 by matrix method.

2x-y+z=6,x+2y+3z=3,3x+y-z=4

Find x ,\ y and z so that A=B , where A=[x-2 3 2z 18 z y+2 6z] , B=[y z6 6y x2y]

Show that : |[x, y, z ],[x^2,y^2,z^2],[x^3,y^3,z^3]|=x y z(x-y)(y-z)(z-x)dot