If : `A=[1 2 0-1 1 2 2-1 1],t h e nA d j(A)=` `[3 5-1-2 1 5 4-2 3]` (b) `[3-5 1 2-1 5 4 2 3]` `[2-2 4 5 1-2-1 5 3]` (d) None of these

What will come next in the series given below ? 1 1 2 1 2 3 1 2 3 4 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 6 1 2 3 4 5 6 7 1 2 3 4 5 1) 1 2) 5 3) 6 4) 2 5) None of these

Let A=[1 2 3-5] and B=[1 0 0 2] and X be a matrix such that A=B X , then X is equal to 1/2[2 4 3-5] (b) 1/2[-2 4 3 5] (c) [2 4 3-5] (d) none of these

Let A=[(1, 2), (3,-5)] and B=[(1, 0), (0, 2)] and X be a matrix such that A=B X , then X is equal to (a) 1/2[(2, 4), (3, -5)] (b) 1/2[(-2, 4), (3, 5)] (c) [(2, 4), (3,-5)] (d) none of these

If A={1,2,3}a n d\ B={1,3,5,7},\ t h e n\ AuuB= {1,2,3,5,7} .

If A=[[-1,5],[-3,2]] , then adj A= (A) [[2,3],[-5,-1]] (B) [[1,-5],[3,-2]] (C) [[2,-5],[3,-1]] ,(D) [[-2,5],[-3,1]]

If A=( (2, -1, 3),( -4, 5 ,1 )) and B( (2, 3 ),(4, -2), (1 ,5) ) then AB and BA=

If A = [(2,2,1), (1,3,1), (1,2,2)] then A^-1+(A-5I) (AI)^2 = (i) 1/ 5 [[4,2, -1], [-1,3,1], [-1,2,4]] (ii) 1/5 [[4, -2, -1], [-1, 3, -1], [-1, -2,4]] (iii) 1/3 [[4,2, -1], [-1,3,1], [-1,2,4]] (iv) 1/3 [[4, -2, -1], [-1,3, -1], [-1, -2,4]]

Let A d+2B=[1 2 0 6-3 3-5 3 1]a n d2A-B=[2-1 5 0-1 6 0 1 2] . Then T r(B) has the value equal to 0 b. 1 c. 2 d. none

If S=(1/2)^2+((1/2)^2 1)/3+((1/2)^3 1)/4+((1/2)^4 1)/5+...... ,t h e n (a) S=ln8-2 (b) S=ln(4/e) (c) S=ln4+1 (d) none of these

If A=[[2/3, 1, 5/3],[ 1/3, 2/3, 4/3] ,[7/3, 2, 2/3]] and B=[[2/3, 3/5, 1],[ 1/5, 2/5, 4/5],[ 7/3, 6/5, 2/5]] , then compute 3A - 5B .