The roots of `ax^2+3bx+c=0` are given by if `3b=a+c` (i) `1,c/a` (ii) `-1,c/a` (iii) `-1,-c/a` (iv) `1,-c/a`

If the roots of ax^(2)+bx+c=0 are -1,-2 then a:b:c

If a,b,c real in G.P.then the roots of the equation ax^(2)+bx+c=0 are in the ratio (1)/(2)(-1+sqrt(3)) b.(1)/(2)(1-i sqrt(3)) c.(1)/(2)(-1-i sqrt(3)) d.(1)/(2)(1+i sqrt(3))

If a+b+c=1 , a^2+b^2+c^2=9 and a^3+b^3+c^3=1 , then 1/a + 1/b + 1/c is (i) 0 (ii) -1 (iii) 1 (iv) 3

If a+b+c=1 , a^2+b^2+c^2=9 and a^3+b^3+c^3=1 , then 1/a + 1/b + 1/c is (i) 0 (ii) -1 (iii) 1 (iv) 3

The roots of the equation ax^2+bx+c=0 will be equal in magnitute but opposite in sign then b= a)0 b)c/a c)1 d)1/a

The roots of a quadratic equation ax^(2) + bx + c=0 are 1 and c/a , then a + b = "_____" .

If the equation ax^(2)+bx+c=0 has non-real roots,prove that 1+(c)/(a)+(b)/(a)>0

If 1/(2-sqrt(-2)) is one of the roots of ax^(2)+bx+c = 0 , where a,b, c are real, then what are the values of a,b,c respectively ?