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If K(a)=10^(-5) for a weak acid, then pK...

If `K_(a)=10^(-5)` for a weak acid, then `pK_(b)` for its conjugate base would be

A

`7`

B

`5`

C

`9`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
C
`Ka = 10^(-5) Ka xx Kb = Kw`
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