How many `H^(+)` ions are present in `10 mL` of a solution having `pH = 10`?

Options

A. `10^(10)`
B. `10^(-10)`
C. `6.02 xx 10^(23)`
D. `6.02 xx 10^(11)`

Answer

D

Explanation

`pH = 10 rArr [H^(+)] = 10^(-10) molL^(-11)`
No. of `H^(+)` in `10 mL`
`= (10)/(1000) xx 6.02 xx 10^(23) xx 10^(-10) = 6.02 xx 10^(11)`