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10 ml of 0.1 N HCl is added to 990 ml so...

`10 ml` of `0.1 N HCl` is added to `990 ml` solution of `NaCl` the `P^(H)` of resulting solution

A

Zero

B

`2`

C

`3`

D

`10`

Text Solution

Verified by Experts

The correct Answer is:
C
`P^(H) = -log(10^(-1)) = 1`
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