The solubility product of a sparingly soluble salt `AX_(2)` is `3.2xx10^(-11)`. Its solubility (in `mo//L`) is

Options

A. `5.6 xx 10^(-6)`
B. `3.1 xx 10^(-4)`
C. `2 xx 10^(-4)`
D. `4 xx 10^(-4)`

Answer

C

Explanation

`AX_(2) hArr A^(2+) + 2X^(-)`
`K_(sp) = 4s^(3) rArr S = ((K_(sp))/(4))^(1//3) = [(3.2 xx 10^(-11))/(4)]^(1//3) = 2 xx 10^(-4)`