The solubility of calcium fluoride in saturated solution, it its solubility product is `3.2 xx 10^(-11)` is :

Options

A. `2.0 xx 10^(-4) M`
B. `12.0 xx 10^(-3) M`
C. `0.2 xx 10^(-4) M`
D. `2.0 xx 10^(-3) M`

Answer

A

Explanation

`CaF_(2) hArr Ca^(2+) + 2F^(-)`
For solubility `'S', K_(sp) = (S) (2S)^(2) = 4S^(3)`
`4S^(3) = 3.2 xx 10^(-11)`
`S^(3) = 8 xx 10^(-12)`
`S = 2 xx 10^(-4) M`