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The P^(H) of a sample of H(2)SO(4) is 1....

The `P^(H)` of a sample of `H_(2)SO_(4)` is `1.3979`. The percentage of the solution is `73.5% (w//w)`, the density of the solution is

A

`2.66 xx 10^(-3) g//c c`

B

`5.32 xx 10^(-3) g// c c`

C

`1.33 xx 10^(-3) g// c c`

D

`0.01 g//c c`

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The correct Answer is:
To find the density of the `H₂SO₄` solution given the pH, percentage concentration, and the equivalent weight, we can follow these steps: ### Step 1: Calculate the concentration of H⁺ ions from pH The pH of the solution is given as `1.3979`. We can calculate the concentration of H⁺ ions using the formula: \[ \text{pH} = -\log[H^+] \] To find [H⁺], we take the antilog: \[ [H^+] = 10^{-\text{pH}} \] Substituting the value of pH: \[ [H^+] = 10^{-1.3979} \approx 4.0 \times 10^{-2} \, \text{mol/L} \] ### Step 2: Determine the normality of the `H₂SO₄` solution For sulfuric acid, `H₂SO₄`, each molecule can release 2 H⁺ ions. Therefore, the normality (N) is twice the molarity (M): \[ N = 2 \times [H^+] = 2 \times 4.0 \times 10^{-2} \approx 8.0 \times 10^{-2} \, \text{N} \] ### Step 3: Use the weight/weight percentage to find the density The weight/weight percentage of `H₂SO₄` is given as `73.5% (w/w)`. This means that in 100 grams of solution, there are 73.5 grams of `H₂SO₄`. ### Step 4: Calculate the equivalent weight of `H₂SO₄` The molecular weight of `H₂SO₄` is approximately 98 g/mol. The equivalent weight (EW) can be calculated as: \[ \text{EW} = \frac{\text{Molecular Weight}}{\text{n}} \] where n is the number of H⁺ ions released per molecule, which is 2 for `H₂SO₄`: \[ \text{EW} = \frac{98}{2} = 49 \, \text{g/equiv} \] ### Step 5: Calculate the density using the normality and equivalent weight The formula for density (d) in terms of normality (N), weight percentage (w/w), and equivalent weight (EW) is: \[ d = \frac{N \times EW}{\text{weight percentage}} \times 10 \] Substituting the values we have: \[ d = \frac{8.0 \times 10^{-2} \times 49}{73.5} \times 10 \] Calculating this gives: \[ d \approx \frac{3.92}{73.5} \times 10 \approx 0.533 \, \text{g/cm}^3 \] ### Final Result Thus, the density of the `H₂SO₄` solution is approximately **0.533 g/cm³**. ---

To find the density of the `H₂SO₄` solution given the pH, percentage concentration, and the equivalent weight, we can follow these steps: ### Step 1: Calculate the concentration of H⁺ ions from pH The pH of the solution is given as `1.3979`. We can calculate the concentration of H⁺ ions using the formula: \[ \text{pH} = -\log[H^+] \] To find [H⁺], we take the antilog: \[ [H^+] = 10^{-\text{pH}} \] Substituting the value of pH: ...
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