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100 ml of a solution of HCl with pH valu...

`100 ml` of a solution of `HCl` with `pH` value `3` is diluted with `400 ml` of water. The new `P^(H)` of the solution is

A

`3.7`

B

`5.3`

C

`4.2`

D

`5.6`

Text Solution

Verified by Experts

The correct Answer is:
A
`100 xx 10^(-3) = 500 xx [H^(+)]`
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