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A one litre contains 0.08 moleof acetic ...

A one litre contains `0.08` moleof acetic acid `(K_(a) = 1.75 xx 10^(-5))`. To this solution of resulting solution is `[log 1.75 = 0.243]`

A

`5.234`

B

`5.058`

C

`4.28`

D

`4.456`

Text Solution

Verified by Experts

The correct Answer is:
C
`CH_(3)COOH + NaOH rArr CH_(3)COONa + H_(2)O`
`[CH_(3)COOH] = 0.08 - 0.02 = 0.06`
`[CH_(3)COONa] = 0.2`
`P^(H) = P^(ka) +"log" (["salt"])/(["acid"])`
`=(5-0.243) + "log" (0.02)/(0.06)`
`= 5 - 0.243) + ["log" 1 - "log" 3]`
`= 5 - 0.243 + 0 - 04771`
`= 5 - 0.7201`
`= 4.28`
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