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A certain volume of 0.001 N NaOH solutio...

A certain volume of `0.001 N NaOH` solution is diluted with `900 mL` of water. The decrease in pH of the soluton is one unit. The original volume of the solution is

A

`1 mL`

B

`10 mL`

C

`100 mL`

D

`1000 mL`

Text Solution

Verified by Experts

The correct Answer is:
C
`P_("Final")^(H) = P_("Initial")^(H) - "log" (V_(2))/(V_(1))`
`1 = - "log" (V_(2))/(V_(1))`
`= - log "(1000)/(V_(1))`
`V_(1) = 100 ml`
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