The dissoctiation of water of `25^(@)C` is `1.9 xx 10^(-7)%` and the density of water is `1g//cm^(3)` the ionisation constant of water is

Options

A. `3.42 xx 10^(-6)`
B. `3.42 xx 10^(-8)`
C. `1.00 xx 10^(-14)`
D. `2.00 xx 10^(-16)`

Answer

D

Explanation

`alpha = 1.9 xx 10^(-7) % = (1.9 xx 10^(-7))/(100) , C= (1000)/(8)` ltbr gt `K_(a) = ([H^(-)][OH^(-)])/([H_(2)O])= Calpha^(2)`
`= 1.9 xx 10^(-9) xx 1.9 xx 10^(-9) xx (1000)/(18) = 2.0 x 10^(-16)`