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K(sp) of a salt ZnCl(2) is 3.2 xx 10^(-8...

`K_(sp)` of a salt `ZnCl_(2)` is `3.2 xx 10^(-8)` its `P^(H)` is

A

`2.3980`

B

`11.6020`

C

`2.6990`

D

Do not calculated exactly

Text Solution

Verified by Experts

The correct Answer is:
A
`ZnCl_(2) rarr underset(S)(Zn^(+2)) + underset(2S)(2Cl^(-))`
`K_(SP) = 4S^(3), S^(3) = 3.2 xx 10^(-8)`
`S = 2 xx 10^(-3) , P^(H) = 3 -2 "log" 2`
`S^(3) = 0.8 xx 10^(-8), S^(3) = 8 xx 10^(-9)`
`S = 2 xx 10^(-3), P^(H) = 3-2 "log" 2`
`= 3-03010 xx 2 , = 3 - 0.602`
`= 2.398`
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