What will be the pH of a solution formed by mixing `40cm^(2)` of `0.1 M HCl` with `10 cm^(3)` of `0.45 M NaOH`

Options

A. `10`
B. `8`
C. `5`
D. `12`

Answer

D

Explanation

No of m eq of `H^(+)` ions `= 40 xx 0.1 = 4`
No of m.e of `OH` ions `= 10 xx 0.45 = 4.5`
`[O^(-)H] = (4.5 - 4)/(50) = (0.5)/(50) = 0.01`
`p^(OH) = -10 g 10^(-2), p^(OH) = 2`
`= p^(H) = 12`