The hydrolysis constant of `NaX` (`K_(a)` of HX is `2 xx 10^(-6)`) is

Options

A. `5 xx 10^(-9)`
B. `2 xx 10^(-8)`
C. `5 xx 10^(-6)`
D. `10^(-7)`

Explanation

To find the hydrolysis constant (K_H) of the salt NaX, we can follow these steps:

### Step 1: Understand the Components
NaX is a salt formed from a strong base (NaOH) and a weak acid (HX). The weak acid has a dissociation constant (K_a) given as \(2 \times 10^{-6}\).

### Step 2: Identify Relevant Constants
We know:
- The ion product of water (K_w) at 25°C is \(1 \times 10^{-14}\).
- The dissociation constant of the weak acid (K_a) is \(2 \times 10^{-6}\).

### Step 3: Use the Hydrolysis Constant Formula
The hydrolysis constant (K_H) for the salt can be calculated using the formula:
\[ K_H = \frac{K_w}{K_a} \]

### Step 4: Substitute the Values
Now, substitute the known values into the formula:
\[ K_H = \frac{1 \times 10^{-14}}{2 \times 10^{-6}} \]

### Step 5: Perform the Calculation
Calculating this gives:
\[ K_H = \frac{1}{2} \times 10^{-14 + 6} = \frac{1}{2} \times 10^{-8} = 5 \times 10^{-9} \]

### Step 6: Conclusion
Thus, the hydrolysis constant \(K_H\) of NaX is \(5 \times 10^{-9}\).