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In the following reaction, AgCl + NaI ...

In the following reaction,
`AgCl + NaI hArr NaCl + AgI`. As `NaI` is added, the equilibrium is shifted towards right giving more `Ag` I precipitate , because

A

Both `AgCl` and `AgI` are sparingly soluble

B

The `K_(sp)` of `AgI` is lower than `K_(sp)` of `AgCl`

C

The `K_(sp)` of `AgI` is higher than `K_(sp)` of `AgCl`

D

Both `AgCl` and `AgI` have same solubility product

Text Solution

Verified by Experts

The correct Answer is:
B

`k_(sp) AgI lt K_(sp) AgC/l`
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