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50 litres of 0.1 M HCl is thoroughly mix...

`50` litres of `0.1 M HCl` is thoroughly mixed with `50` litres of `0.2 M NaOH` The `pOH` of the resulting solution is

A

`1.0`

B

`0.0`

C

`7.0`

D

`1.30`

Text Solution

Verified by Experts

The correct Answer is:
D
`[OH^(-)] = (50 xx 0.2 - 50 xx 0.1)/((50 + 50))`
`= (10 - 5)/(100) = (5)/(100) = 0.05`
`= 5 xx 10^(-2)`
`P^(OH) = - "log"_(10)[OH^(-)]`
`= - "log"_(10) 5 xx 10^(-2)`
`= 2 - "log"(10) 5`
`= 2 - 0.6990 = 1.3`
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