The concentration of an oxlic acid solution is `x` mol `litre^(-1)` . 40mL of this solution reacts with 16 mL of 0.05 M acidified `KMnO_(4)`. What is the pH `x` M oxalic acid solution ? (Assume that oxalic acid dissociates completely.)

Options

A. `1.3`
B. `1.699`
C. `1`
D. `2`

Answer

C

Explanation

for any redox reaction
`(M_(1)V_(1))/(n_(1)) = (M_(2)V_(2))/(n_(2))`
`2` moles `KMnO_(4)` completely oxidised by
`(0.05 xx 16)/(2) = (x xx 40)/(5)`
`x = 0.05 M`
'Normality' of Oxalic acid `= 0.05x2 = 0.1`
`P^(H) = 1`