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Equal volume of 0.1 M potassium hydroxid...

Equal volume of `0.1 M` potassium hydroxide and `0.1 M` sulphuric acid are mixed. The `P^(H)` of resulting solution is

A

`7`

B

`0`

C

`gt 7`

D

`lt 7`

Text Solution

Verified by Experts

The correct Answer is:
D
normality of acid `gt` normality of base, so resultant solution is acidic in nature
`(N_(2)V_(2)- N_(1)V_(1))/(V_(1) + V_(2)) = (V[0.2 - 0.1])/(2V) = 0.1/2 = 0.05N`
`"acid" lt 7`
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