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A solution contains 60 mL of 0.1 M NH(4)...

A solution contains `60 mL` of `0.1 M NH_(4)OH` and `30 mL` of `0.1 MHCl`. The `P^(H)` of the resulting mixture is
(Given `K_(b)` of `NH_(4)OH = 1.8 xx 10^(-5)`,
`1.8 = 0.2553`)

A

`4.7447`

B

`3.7447`

C

`9.2553`

D

`12.523`

Text Solution

Verified by Experts

The correct Answer is:
C
`NH_(4)OH + HCl rarr NH_(4)Cl + H_(2)O `
`[NH_(4)OH] = 60 xx 0.1 - 30 xx 0.1`
`[NH_(4)Cl] = 30 xx 0.1`
`:. P^(H) = 14 - P^(kb)`
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