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Find moles of NH(4)Cl required to preven...

Find moles of `NH_(4)Cl` required to prevent `Mg(OH)_(2)` from precipitating in a litre of solution which contains 0.02 mole `NH_(3)` and 0.001 mole `Mg^(2+)` ions.
Given : `K_(b)(NH_(3))=10^(-5),` `K_(sp)[Mg(OH)_(2)]=10^(-11)`.

A

`10^(-4)`

B

`2 xx 10^(-3)`

C

`0.02`

D

`0.1`

Text Solution

Verified by Experts

The correct Answer is:
B

`[OH^(-)]= sqrt((K_(SP))/([Mg^(2+)])) = sqrt((10^(-11))/(10^(-3))) = 10^(-4)`
`rArr pOH = pK_(b) + "log" ([NH_(4)Cl])/([NH_(3)])`
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