`0.1` millimole of `CdSO_(4)` are present in 10 mL acid solution of `0.08N HCI`. Now `H_(2)S` is passed to precipitate all the `Cd^(2+)` ions. The pH of the solution after filtering off precipitate, boiling of `H_(2)S` and making the solution 100 mL by adding `H_(2)O`, is:

Answer

2