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Calculate the percentage hydrolysis in 0...

Calculate the percentage hydrolysis in `0.003M` aqueous solution of NaOCN. `(K_(a)for HOCN=3.33xx10^(-4))`

A

`10^(-3)`

B

`10^(-2)`

C

`10^(-4)`

D

`10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
B
`NaOCN + H_(2)O hArr NaOH + HCN`
`h = sqrt((K_(H))/(C)) = sqrt((K_(W))/(K_(a)xxc))`
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