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Neutralisation constant of HCOOH with a ...

Neutralisation constant of `HCOOH` with a strong bse is `10^(8)`. What is the `pH` of `0.01 M HCOOK` solution at `25^(0)C`?

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The correct Answer is:
9

`HCOOH + KOH hArr HCOOK + H_(2)O`
`K_("neu") = (1)/(K_(h)) = (K_(a))/(K_(w))`
`K_(a) = 10^(8) xx 10^(-14) = 10^(-6) , pH = 7+3-1 = 9`
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