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The fraction of total volume occupied by...

The fraction of total volume occupied by atoms in a simple cube is

A

`(pi)/(6)`

B

`(pi)/(3sqrt(2))`

C

`(pi)/(4sqrt(2))`

D

`(pi)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
1

Packing fraction in simple cube
`((4)/(3)pir^(3))/(a^(3))` here `a=2r, therefore ((4)/(3)pir^(3))/((2r)^(3))=(pi)/(6)`
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