The composition of a sample of wrustite is `Fe_(0.93)O_(1.00)`.Percentage of iron present in the form of iron (III) is nearly

Options

A. 85
B. 15
C. `7.00`
D. `93.00`

Answer

2

Explanation

Let, the sample contains 93 Iron ions and 100 oxide ions.
Total negative charge on oxide ions`=100xx-2=-200`
No. of `Fe^(+3)`ions=x
No. of `Fe^(+2)` iron ions =93-x
Total positive charge `=x(+3)+(93-x)(+2)`
Numarically +ve charge and -ve charge
are equal `therefore 3x+(93-x)2=200 therefore x=14`
% of `Fe^(+3)=(14)/(93)xx100=15.05%`