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Experimentally it was found that a metal...

Experimentally it was found that a metal oxide in formula `M_(0.98)O`. Metal `M` is present as `M^(2+)` and `M^(3+)` in its oxide ,Fraction of the metal which exists as `M^(3+)` would be

A

0.0505

B

0.0701

C

0.0408

D

0.0605

Text Solution

Verified by Experts

The correct Answer is:
`3`
Let the fraction of metal which exists as `M^(3+)` be x. then the fraction of metal as `M^(2+)=(0.98-x)`.
`therefore 3x+2(0.98-x)=2`
`x=0.04 therefore % "of" M^(2+)=(0.04)/(0.98)xx100=4.08%`
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