Iron has body centred cubic lattice. If the edge length of the unit cell is 286 pm, the radius of iron atom is

Options

A. 50.3g/cc
B. 63.4g/cc
C. 41.6g/cc
D. 34.8g/cc

Explanation

a=200pm `=2xx10^(-8)` cm
`v=a^(3)=8xx10^(-24)cm^(2)`
mass of unit cell `=(200xx4)/(24xx10^(23))`
`=33.3xx10^(-23)g`
density `(m)/(v)=(33.3xx10^(-23))/(8xx10^(-24))=41.6g//cc`