If 1 mole of NaCl is doped with `10^(-3)` mole of `SrCl_(2)`. What is the number of cationic vacancies per mole of NaCl ?

Options

A. `6.023xx10^(20)`
B. `6.023xx10^(23)`
C. `6.023xx10^(21)`
D. `6.023xx10^(18)`

Explanation

no. of moles of `Sr^(+2)` added `=10^(-3)xx(1)/(100)=10^(-5)` moles
no. of `Sr^(+2)` ions added
`=6.023xx10^(23)xx10^(-5)=6.023xx10^(18)`