For the spinel structure `(MgAl_(2)O_(4))`, the correct statement is/are

Options

A. 50% Ovs are occupied by ions.
B. `Al^(3+)` is equally distributed in TVs and Ovs.
C. Oxide ions occupy ccp lattice.
D. 12.5% TVs are occupied by ions.

Explanation

For spinel structure `O^(2-)` ions form fcc arrangement.
`therefore ` Number of `O^(2-)` ions =4.
Number of TV=8, Number of OV=4
Number of `Mg^(2+)` ions `=(1)/(8)xxTV =(1)/(8)xx8=1`
Number of `Al^(3+)` ions `=(1)/(2)xxOV=(1)/(2)xx4=2`
So, 50%OVs are occuped and 1/8th , i.e., 12.5% TVs are occupied.