Home
Class 11
CHEMISTRY
The density of solid Ar (Ar=40 g/mole) i...

The density of solid Ar (Ar=40 g/mole) is 1.68 g/ml at 40 K. if the argon atom is assumed to be a sphere of radius `1.50xx10^(-8)cm`, then % of solid Ar is apparently empty space?

A

`35.64`

B

`64.36`

C

`74 %`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

vol, solid Ar `=1 cm^(3)` vol,
atoms `=(1.68)/(40)xxN_(0)xx(4)/(3)xx(22)/(7)xx(1.5)^(3)xx10^(-24)=0.3564`
Promotional Banner

Similar Questions

Explore conceptually related problems

The density of solid argon is 1.65g//mL at -233^(@)C . If the argon atom is assumed to be sphere of radius 1.54xx10^(-8)cm , what percentage of solid argon is apparentaly empty space ? (At. Wt. of Ar=40)

The density of solid argon is (2)/(3) ("amu"//Å^(3)) at 40K. If the Argon atom is assumed to be sphere to radius (3)/(pi^(1//3)) Å , what percentage of solid Argon is apparently withput anything ?

The density of a solution containing 40% by mass of HCl is 1.2 g/mL. Calculate the molarity of the solution.

The density of copper is "8.94 g mL"^(-1) . Find the charge needed to plate an area of 10xx10cm^(2) to a thickness of 10^(-2)cm using a CuSO_(4) solution as electrolyte (atomic weight of Cu = 63.6 g/mol).

In a Moon rock sample the ratio of number of (stable) ""^(40)Ar atoms present to the number of (radioactive) ""^(40)K atoms is 10.3. Assume that all the argon atoms were produced by the decay of potassium atoms, with a half life of 1.25xx10^(9)y . How old is the rock?

Assuming atom to be a sphere, the radius of atom would be [if the apparent volume of atom of a metal is 1.23xx10^(-23)mL ]