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First three nearest neighboure distance...

First three nearest neighboure distance for primitive cubic lattice are respectively (edge length of unit cell = a):

A

`a, sqrt2 a, sqrt3 a`

B

`sqrt3 a , sqrt2 a , a`

C

`a , sqrt2 a , 2a`

D

`a , sqrt3 a , 2a`

Text Solution

Verified by Experts

The correct Answer is:
A

AB=a (nearest)
`BD=sqrt(2)a` (next-nearest)
`CE=sqrt(3)a` (next-next-nearest)
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