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Twenty precent of the surface sites of a...

Twenty precent of the surface sites of a catalyst is occupied by nitrogen molecules. The density of surface sites is `6.023xx10^(14)cm^(-2)` . The total sarface area is `1000cm^(2)` . The catalyst is is henced to `300K` and nitrogen is completely desorbed a pressure of `0.001` atm and volume of `2.46cm^(3)` . Calculate the number of sites occupied by niitrogen molecules.

Text Solution

Verified by Experts

The correct Answer is:
2
`N_(2)=0.001` atm: `T=300K, V=2.46cm^(3)`
`therefore` Number of `N_(2)` molecules
`=(PV)/(RT)xxN_(0)=(0.001xx2.46xx10^(-3))/(0.082xx300)xx6.023xx10^(23)=6.016xx10^(16)`
Now, total number of surface sites
=DensityxxxTotal surface area =`6.023xx10^(14)xx1000=6.023xx10^(17)`
Site occupied by `N_(2)` molecules `=(20)/(100)xx6.023xx10^(!7)=12.04xx10^(!6)`
`therefore` Number of stites occupied by each `N_(2)`
molecule `=(12.04xx10^(16))/(6.016xx10^(16))=2`
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