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Silver (atomic weight 108 g mol^(-1)) ha...

Silver (atomic weight `108 g mol^(-1))` has a density of `10.5 g cm^(-3)`. The number of silver atoms on a surfaces of area `10^(-12) m^(2)` can be expressed in scientific notation as `Y xx 10^(-x)`, The value of `x` is …….

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The correct Answer is:
7
7
Hint: Ag crystallises in FCC unit cell with 4 atoms per unit cell.
`rho=(4xx108)/(6.023xx10^(23)xxa^(3))=10.5g cm^(-3)`
`rArr a^(3)` (Volume of unit cell) `=6.83xx10^(-23) cm^(3)`
`rArra=4xx10^(-8)cm=4xx10^(-10)m `
`rArr` Surface area of unit cell=
`a^(2)=1.6xx10^(-19)m^(2)`
`rArr` Number of unit cells on `10^(-12)m^(2)` surface
`(10^(-1))/(1.6xx10^(-19))=6.25xx10^(6)`
`because` There are two atoms (effectively) on one face of unit cell
Number of atoms on `10^(-12)m^(2)` surface=2xx number of unit cell=`1.25xx10^(7).rArrx=7`
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