Home
Class 11
CHEMISTRY
The number of hexagonal faces that are p...

The number of hexagonal faces that are present in a truncated octahedron is

Text Solution

Verified by Experts

The correct Answer is:
8
The truncated octahedron is the 14-faced Archimedean solid, with 14 solid faces: 6 squares and 8 regular hexagons.

The truncated octahedron is formed by removing the six right square pyramids one from each point of a regular octahedron as:

Truncated octahedron unfolded in two dimensions.
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the number of hexagonal faces that are present in a truncated octahedral.

An octahedron has

Please help Sabu decode the jail lock. Chacha Choudhary gave Sabu a formula : f_(1) = ((x)/(z)xx y), f_(2) =((f)/(v) xxu), f_(3) = ((r)/(s)xx w) Sabu can open the lock if he finds the value of 3f_(1) +f_(2) +f_(3) = key where: Number of triangular faces in a truncated tetrahedron = x Number of hexagonal faces in a truncated tetrahedron = x Number of corners in a truncated tetrahedron = z Number of square faces in a truncated octahedron = t Number of hexagonal faces in a truncated octahedron = u Number of corners in a truncated octahedron = u Number of triangular faces in a truchcated cube = w Number of octangonal faces in a truncated cube = r Number of corners in a truncated cube = s What is the KEY ?

Cis - and trans - faces are present in

The number of faces in the given figure is

The number of faces in the given figure is