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If (5)(7/x)xx(y)1/(13)=12 where fraction...

If `(5)(7/x)xx(y)1/(13)=12` where fractions are in their lowest terms then value of x-y=

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`5 7/x xx y 1/13 = 12`
`=>(5x+7)/x xx (13y+1)/13 = 12`
Now, it is given that the fractions are in their lowest terms.
` :. (5x+7)` should be a multple of `13` and `(13y+1)` should be a multiple of `x`.
`:. 5x+7 = 13N and 13y+1 = xM`, where `M` and `N` are whole numbers.
`:. (13N)/x xx (xM)/13 = 12`
`=>MN = 12`
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