Let ` cos (alpha+beta) = 4/5` and `sin(alpha-beta)=5/13 ` where `0<= alpha,beta<= pi/4` then find ` tan (2alpha)`

Let cos(alpha+beta) =4/5 and let sin (alpha-beta)=5/13 where 0 le alpha, beta le (pi)/(4) then tan 2 alpha

Let cos(alpha+beta)=4//5and let sin(alpha-beta)=5//13 , where 0lealpha,betalepi//4 . Then tan2alpha is equal to

Let cos(alpha+beta)""=4/5 and let sin (alpha-beta)""=5/(13) where 0lt=alpha,betalt=pi/4 , then t a n""2alpha= (1) (56)/(33) (2) (19)/(12) (3) (20)/7 (4) (25)/(16)

Let cos(alpha+beta)""=4/5 and let sin (alpha+beta)""=5/(13) where 0lt=alpha,betalt=pi/4 , then t a n""2alpha=

Let cos(alpha+beta)=(4)/(5) and let sin(alpha-beta)=(5)/(13) , where 0 le alpha , beta=(pi)/(4) . Then tan2alpha=

Let cos(alpha+beta)=(4)/(5) and let sin(alpha-beta)=(5)/(13), where 0<=alpha,beta<=(pi)/(4) Then tan2 alpha=(36)/(33) b.(19)/(12) c.(20)/(7)d*(25)/(16)