Solve: `dy/dx + y tan x = 3x^2 + x^3 tan x, x!=(pi )/2`, given that `y = 0` when `x = (pi)/3`.

(dy)/(dx) + y tan x = 2x + x ^(2) tan x , given that y = 1 when x=0

(dy)/(dx) + 2 y tan x = sin x, y = 0 when x = (pi)/(3) .

2 (dy) / (dx) -y sec x = y ^ (3) tan x

dy/dx + 2y tan x = sinx, give y = 0 when x= pi/3

dy/dx - 3y cot x = sin 2x, given y= 2 when x = pi/ 2

The solution of (dy)/(dx) + 2y tan x = sin x , given that y = 0, x =(pi)/(3) is

Find the particular solution of differential equation : tan x dy/dx+y=2x tan x + x^2,xne0 , given that y=0 when x=pi/2 .

Solve: x (dy)/(dx)- y-x tan . (y/x) . = 0

Solve (dy)/(dx) + y = tan x (0 le x lt (pi)/(2))