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If a = 2x , initially particle is at x =...

If a = 2x , initially particle is at x = 2m and is moving with `3ms^(-1)`. Then find out v at x=5m

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Given a=2x
`implies(vdv)/(dx)=2x" "impliesint_3^v vdv=int_2^5 2xdx`
`implies(v^2)/2-9/2=25-4impliesv^2-9=21xx2`
`impliesv=sqrt(51)ms^(-1)`
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