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A body is projected with a velocity of 3...

A body is projected with a velocity of `30 ms^(-1)` at an angle of `30^(@)` with the vertical. Find the maximum height, time of flight and the horizontal range.

Text Solution

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Here `u=20ms^(-1)`
Angle of projection , `theta=90-30=60^(@)`
Maximum height,
`H=(u^2sin^2theta)/(2g)=(30^2 sin^260^(@))/(2xx9.8)=34.4m`
Time of flight
`T=(2u sintheta)/(g)=(2xx30 sin60^(@))/(9.8)=5.3s`
Horizonatal range,
`R(u^2sin2theta)/(g)=(30^(@)sin120^(@))/(9.8)=(30^2sin60^(@))/(9.8)=79.53m`
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