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A body is projected with a velocity of 2...

A body is projected with a velocity of `20 ms^(-1)` in a direction making an angle of `60^(@)` with the horizontal. Determine its (i) position after 0.5 s and (ii) the velocity after `0.5s`.

Text Solution

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Here `u=20ms^(-1),theta=60^(@),t=0.5s`
`x=(u costheta)t=(20 cos60^(@))xx0.5=5m`
`y=(usintheta)t1/2g t^2=(20xxsin60^(@))xx0.5`
`-1/2xx9.8xx(0.5)^2=7.43m`
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