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A body is projected with a velocity of 2...

A body is projected with a velocity of `20 ms^(-1)` in a direction making an angle of `60^(@)` with the horizontal. Determine its (i) position after 0.5 s and (ii) the velocity after `0.5s`.

Text Solution

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`v_x=ucostheta=20cos60^(@)=10ms^(-1)`
`v_y=usintheta-"gt"=20sin60^(@)-9.58xx0.5`
`=12.42ms^(-1)`
`:. V=sqrt(v_x^2+v_y^2)=sqrt((10)^2+(12.42)^2)=15.95ms^(-1)`
`tanbeta=(v_y)/(v_x)=(12.42)/(10)=1.242`
`:. Beta=tan^(-1)1.242=51.16^(@)`
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