A body is thrown upward and reaches its maximum height. At that position-

Options

A. its velocity is zero and its acceleration is also zero
B. its velocity is zero but its acceleration is maximum
C. its acceleration is minimum
D. its velocity is zero and its acceleration is the acceleration due to gravity

Answer

To solve the problem, we need to analyze the motion of a body thrown upward when it reaches its maximum height. Here’s a step-by-step breakdown of the situation:

### Step 1: Understanding the Motion
When a body is thrown upward, it moves against the force of gravity until it reaches its maximum height. At this point, the body momentarily stops before it starts to fall back down.

**Hint:** Remember that at maximum height, the velocity of the body is zero.

### Step 2: Analyzing Velocity at Maximum Height
At the maximum height, the velocity of the body is zero (v = 0). This is because it has reached the peak of its trajectory and is about to change direction.

**Hint:** Think about what happens to an object thrown upwards; it must stop before coming back down.

### Step 3: Analyzing Acceleration at Maximum Height
Even though the velocity is zero at maximum height, the acceleration is not zero. The body is still under the influence of gravity, which acts downwards with an acceleration of approximately \(9.81 \, \text{m/s}^2\) (denoted as \(g\)).

**Hint:** Acceleration due to gravity is always acting on the object, regardless of its velocity.

### Step 4: Conclusion
At the maximum height:
- **Velocity (v)** = 0
- **Acceleration (a)** = \(g\) (which is negative in the upward direction)

Thus, the correct statement regarding the body at maximum height is:
- Velocity is 0 and acceleration is equal to the acceleration due to gravity (which is acting downward).

**Final Answer:** Velocity is 0 and acceleration is equal to the acceleration due to gravity.